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v0.5.1
https://github.com/python/cpython
Revision d8948c5e09c4a2a818f6f6cfaf8064f2c2138fa5 authored by Miss Islington (bot) on 29 May 2018, 22:37:06 UTC, committed by GitHub on 29 May 2018, 22:37:06 UTC

Currently, asyncio.wait_for(fut), upon reaching the timeout deadline,
cancels the future and returns immediately.  This is problematic for
when *fut* is a Task, because it will be left running for an arbitrary
amount of time.  This behavior is iself surprising and may lead to
related bugs such as the one described in bpo-33638:

    condition = asyncio.Condition()
    async with condition:
        await asyncio.wait_for(condition.wait(), timeout=0.5)

Currently, instead of raising a TimeoutError, the above code will fail
with `RuntimeError: cannot wait on un-acquired lock`, because
`__aexit__` is reached _before_ `condition.wait()` finishes its
cancellation and re-acquires the condition lock.

To resolve this, make `wait_for` await for the task cancellation.
The tradeoff here is that the `timeout` promise may be broken if the
task decides to handle its cancellation in a slow way.  This represents
a behavior change and should probably not be back-patched to 3.6 and
earlier.
(cherry picked from commit e2b340ab4196e1beb902327f503574b5d7369185)

Co-authored-by: Elvis Pranskevichus <elvis@magic.io>
1 parent 0364342
History
Tip revision: d8948c5e09c4a2a818f6f6cfaf8064f2c2138fa5 authored by Miss Islington (bot) on 29 May 2018, 22:37:06 UTC
bpo-32751: Wait for task cancellation in asyncio.wait_for() (GH-7216)
Tip revision: d8948c5

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