Staging
v0.8.1
Revision 5b956ca42de37c761562e9c9aeb96a0e67606e33 authored by Pablo Galindo on 11 May 2020, 00:41:26 UTC, committed by GitHub on 11 May 2020, 00:41:26 UTC
With the new parser, the error message contains always the trailing
newlines, causing the comparison of the repr of the error messages
in codeop to fail. This commit makes the new parser mirror the old parser's
behaviour regarding trailing newlines.
1 parent 2cc9b84
Raw File
nturl2path.py
"""Convert a NT pathname to a file URL and vice versa.

This module only exists to provide OS-specific code
for urllib.requests, thus do not use directly.
"""
# Testing is done through test_urllib.

def url2pathname(url):
    """OS-specific conversion from a relative URL of the 'file' scheme
    to a file system path; not recommended for general use."""
    # e.g.
    #   ///C|/foo/bar/spam.foo
    # and
    #   ///C:/foo/bar/spam.foo
    # become
    #   C:\foo\bar\spam.foo
    import string, urllib.parse
    # Windows itself uses ":" even in URLs.
    url = url.replace(':', '|')
    if not '|' in url:
        # No drive specifier, just convert slashes
        if url[:4] == '////':
            # path is something like ////host/path/on/remote/host
            # convert this to \\host\path\on\remote\host
            # (notice halving of slashes at the start of the path)
            url = url[2:]
        components = url.split('/')
        # make sure not to convert quoted slashes :-)
        return urllib.parse.unquote('\\'.join(components))
    comp = url.split('|')
    if len(comp) != 2 or comp[0][-1] not in string.ascii_letters:
        error = 'Bad URL: ' + url
        raise OSError(error)
    drive = comp[0][-1].upper()
    components = comp[1].split('/')
    path = drive + ':'
    for comp in components:
        if comp:
            path = path + '\\' + urllib.parse.unquote(comp)
    # Issue #11474 - handing url such as |c/|
    if path.endswith(':') and url.endswith('/'):
        path += '\\'
    return path

def pathname2url(p):
    """OS-specific conversion from a file system path to a relative URL
    of the 'file' scheme; not recommended for general use."""
    # e.g.
    #   C:\foo\bar\spam.foo
    # becomes
    #   ///C:/foo/bar/spam.foo
    import urllib.parse
    if not ':' in p:
        # No drive specifier, just convert slashes and quote the name
        if p[:2] == '\\\\':
        # path is something like \\host\path\on\remote\host
        # convert this to ////host/path/on/remote/host
        # (notice doubling of slashes at the start of the path)
            p = '\\\\' + p
        components = p.split('\\')
        return urllib.parse.quote('/'.join(components))
    comp = p.split(':')
    if len(comp) != 2 or len(comp[0]) > 1:
        error = 'Bad path: ' + p
        raise OSError(error)

    drive = urllib.parse.quote(comp[0].upper())
    components = comp[1].split('\\')
    path = '///' + drive + ':'
    for comp in components:
        if comp:
            path = path + '/' + urllib.parse.quote(comp)
    return path
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