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Tip revision: 49b5230a6c058e56d0f57c844327f0ca77352767 authored by cvs2svn on 25 July 2003, 01:12:48 UTC
This commit was manufactured by cvs2svn to create tag 'r23c2'.
Tip revision: 49b5230
test_heapq.py
"""Unittests for heapq."""

from test.test_support import verify, vereq, verbose, TestFailed

from heapq import heappush, heappop, heapify, heapreplace
import random

def check_invariant(heap):
    # Check the heap invariant.
    for pos, item in enumerate(heap):
        if pos: # pos 0 has no parent
            parentpos = (pos-1) >> 1
            verify(heap[parentpos] <= item)

# An iterator returning a heap's elements, smallest-first.
class heapiter(object):
    def __init__(self, heap):
        self.heap = heap

    def next(self):
        try:
            return heappop(self.heap)
        except IndexError:
            raise StopIteration

    def __iter__(self):
        return self

def test_main():
    # 1) Push 100 random numbers and pop them off, verifying all's OK.
    heap = []
    data = []
    check_invariant(heap)
    for i in range(256):
        item = random.random()
        data.append(item)
        heappush(heap, item)
        check_invariant(heap)
    results = []
    while heap:
        item = heappop(heap)
        check_invariant(heap)
        results.append(item)
    data_sorted = data[:]
    data_sorted.sort()
    vereq(data_sorted, results)
    # 2) Check that the invariant holds for a sorted array
    check_invariant(results)
    # 3) Naive "N-best" algorithm
    heap = []
    for item in data:
        heappush(heap, item)
        if len(heap) > 10:
            heappop(heap)
    heap.sort()
    vereq(heap, data_sorted[-10:])
    # 4) Test heapify.
    for size in range(30):
        heap = [random.random() for dummy in range(size)]
        heapify(heap)
        check_invariant(heap)
    # 5) Less-naive "N-best" algorithm, much faster (if len(data) is big
    #    enough <wink>) than sorting all of data.  However, if we had a max
    #    heap instead of a min heap, it could go faster still via
    #    heapify'ing all of data (linear time), then doing 10 heappops
    #    (10 log-time steps).
    heap = data[:10]
    heapify(heap)
    for item in data[10:]:
        if item > heap[0]:  # this gets rarer the longer we run
            heapreplace(heap, item)
    vereq(list(heapiter(heap)), data_sorted[-10:])
    # 6)  Exercise everything with repeated heapsort checks
    for trial in xrange(100):
        size = random.randrange(50)
        data = [random.randrange(25) for i in range(size)]
        if trial & 1:     # Half of the time, use heapify
            heap = data[:]
            heapify(heap)
        else:             # The rest of the time, use heappush
            heap = []
            for item in data:
                heappush(heap,item)
        data.sort()
        sorted = [heappop(heap) for i in range(size)]
        vereq(data, sorted)
    # Make user happy
    if verbose:
        print "All OK"

if __name__ == "__main__":
    test_main()
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